Leaves-Yasmin #41
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Leaves-Yasmin #41
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CheezItMan
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Sep 19, 2019
| index_1 = 0 | ||
| array.times do | ||
| if list[index_1] == list[index_1 + 1] | ||
| list.delete_at(index_1) |
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Actually delete_at will remove the element at index_1 by shifting all the subsequent elements left by one index. So it's an O(n) method. Since you have it nested in a loop running n times. This is actually an O(n2) method.
| end | ||
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| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| # Time Complexity: o(n^2) |
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This is actually O(mn) where m is the length of the strings and n is the number of strings.
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